20220523,模板
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@@ -18,9 +18,10 @@ coverImg:
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img:
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password:
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---
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[toc]
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# Markdown
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## Markdown索引
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@@ -60,7 +61,7 @@ password:
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**[PicGo + Gitee(码云)实现免费markdown图床](https://link.zhihu.com/?target=https%3A//www.jianshu.com/p/b69950a49ae2)**
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### HTML插入-排版
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@@ -106,11 +107,11 @@ password:
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我们以网易云音乐为例 1.首先在网易云音乐播放界面，点击生成外链播放器
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<iframe frameborder="no" border="0" marginwidth="0" marginheight="0" width=330 height=86 src="//music.163.com/outchain/player?type=2&id=1858139145&auto=0&height=66">
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</iframe>
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@@ -253,6 +254,44 @@ $$
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根式使用`\sqrt[a]b`来表示。其中，方括号内的值用来表示开几次方，省略方括号则表示开方，如`\sqrt[4]{\frac xy}`：$\sqrt[4]{\frac xy}$，`\sqrt{x^3}`：$\sqrt{x^3}$。
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#### 矩阵
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```latex
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\left[ \begin{matrix}
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x11 & x12 \\x21 & x22\\
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\end{matrix} \right]
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```
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前后用\left和\right包围，[]标识用方括号
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$$
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\left[ \begin{matrix}
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x11 & x12 \\x21 & x22\\
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\end{matrix} \right]
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$$
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```latex
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\left[\begin{matrix}
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p_{11}&p_{12}\\p_{21}&p_{22}\\
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\end{matrix}\right]_k^-=\left[\begin{matrix}
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1&dt\\0&1\\
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\end{matrix}\right]
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\left[\begin{matrix}
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p_{11}&p_{12}\\p_{21}&p_{22}\\
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\end{matrix}\right]_{k-1}
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\left[\begin{matrix}
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1&0\\dt&1\\
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\end{matrix}\right]
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+\left[\begin{matrix}
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Q_{11}&Q_{12}\\Q_{21}&Q_{22}\\
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\end{matrix}\right]
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```
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$$
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\left[\begin{matrix}p_{11}&p_{12}\\p_{21}&p_{22}\\\end{matrix}\right]_k^-=\left[\begin{matrix}1&dt\\0&1\\\end{matrix}\right]\left[\begin{matrix}p_{11}&p_{12}\\p_{21}&p_{22}\\\end{matrix}\right]_{k-1}\left[\begin{matrix}1&0\\dt&1\\\end{matrix}\right]+\left[\begin{matrix}Q_{11}&Q_{12}\\Q_{21}&Q_{22}\\\end{matrix}\right]
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$$
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#### 字体
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- 使用`\it`显示意大利体（公式默认字体）：$ACDEFGHIJKLMnopqrstuvwxyz$。
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@@ -262,13 +301,13 @@ $$
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### MarkDown符号大全
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